\(\int \frac {\sqrt {x}}{(a x+b x^3+c x^5)^{3/2}} \, dx\) [118]

Optimal result

Integrand size = 24, antiderivative size = 103 \[ \int \frac {\sqrt {x}}{\left (a x+b x^3+c x^5\right )^{3/2}} \, dx=\frac {\sqrt {x} \left (b^2-2 a c+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {a x+b x^3+c x^5}}-\frac {\text {arctanh}\left (\frac {\sqrt {x} \left (2 a+b x^2\right )}{2 \sqrt {a} \sqrt {a x+b x^3+c x^5}}\right )}{2 a^{3/2}} \]

[Out]

-1/2*arctanh(1/2*(b*x^2+2*a)*x^(1/2)/a^(1/2)/(c*x^5+b*x^3+a*x)^(1/2))/a^(3/2)+(b*c*x^2-2*a*c+b^2)*x^(1/2)/a/(-
4*a*c+b^2)/(c*x^5+b*x^3+a*x)^(1/2)

Rubi [A] (verified)

Time = 0.04 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {1936, 1927, 212} \[ \int \frac {\sqrt {x}}{\left (a x+b x^3+c x^5\right )^{3/2}} \, dx=\frac {\sqrt {x} \left (-2 a c+b^2+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {a x+b x^3+c x^5}}-\frac {\text {arctanh}\left (\frac {\sqrt {x} \left (2 a+b x^2\right )}{2 \sqrt {a} \sqrt {a x+b x^3+c x^5}}\right )}{2 a^{3/2}} \]

[In]

Int[Sqrt[x]/(a*x + b*x^3 + c*x^5)^(3/2),x]

[Out]

(Sqrt[x]*(b^2 - 2*a*c + b*c*x^2))/(a*(b^2 - 4*a*c)*Sqrt[a*x + b*x^3 + c*x^5]) - ArcTanh[(Sqrt[x]*(2*a + b*x^2)
)/(2*Sqrt[a]*Sqrt[a*x + b*x^3 + c*x^5])]/(2*a^(3/2))

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 1927

Int[(x_)^(m_.)/Sqrt[(b_.)*(x_)^(n_.) + (a_.)*(x_)^(q_.) + (c_.)*(x_)^(r_.)], x_Symbol] :> Dist[-2/(n - q), Sub
st[Int[1/(4*a - x^2), x], x, x^(m + 1)*((2*a + b*x^(n - q))/Sqrt[a*x^q + b*x^n + c*x^r])], x] /; FreeQ[{a, b,
c, m, n, q, r}, x] && EqQ[r, 2*n - q] && PosQ[n - q] && NeQ[b^2 - 4*a*c, 0] && EqQ[m, q/2 - 1]

Rule 1936

Int[(x_)^(m_.)*((b_.)*(x_)^(n_.) + (a_.)*(x_)^(q_.) + (c_.)*(x_)^(r_.))^(p_), x_Symbol] :> Simp[(-x^(m - q + 1
))*(b^2 - 2*a*c + b*c*x^(n - q))*((a*x^q + b*x^n + c*x^(2*n - q))^(p + 1)/(a*(n - q)*(p + 1)*(b^2 - 4*a*c))),
x] + Dist[(2*a*c - b^2*(p + 2))/(a*(p + 1)*(b^2 - 4*a*c)), Int[x^(m - q)*(a*x^q + b*x^n + c*x^(2*n - q))^(p +
1), x], x] /; FreeQ[{a, b, c}, x] && EqQ[r, 2*n - q] && PosQ[n - q] &&  !IntegerQ[p] && NeQ[b^2 - 4*a*c, 0] &&
IGtQ[n, 0] && LtQ[p, -1] && RationalQ[m, p, q] && EqQ[m + p*q + 1, (-(n - q))*(2*p + 3)]

Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {x} \left (b^2-2 a c+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {a x+b x^3+c x^5}}+\frac {\int \frac {1}{\sqrt {x} \sqrt {a x+b x^3+c x^5}} \, dx}{a} \\ & = \frac {\sqrt {x} \left (b^2-2 a c+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {a x+b x^3+c x^5}}-\frac {\text {Subst}\left (\int \frac {1}{4 a-x^2} \, dx,x,\frac {\sqrt {x} \left (2 a+b x^2\right )}{\sqrt {a x+b x^3+c x^5}}\right )}{a} \\ & = \frac {\sqrt {x} \left (b^2-2 a c+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {a x+b x^3+c x^5}}-\frac {\tanh ^{-1}\left (\frac {\sqrt {x} \left (2 a+b x^2\right )}{2 \sqrt {a} \sqrt {a x+b x^3+c x^5}}\right )}{2 a^{3/2}} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.05 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.19 \[ \int \frac {\sqrt {x}}{\left (a x+b x^3+c x^5\right )^{3/2}} \, dx=-\frac {\sqrt {x} \left (\sqrt {a} \left (b^2-2 a c+b c x^2\right )+\left (b^2-4 a c\right ) \sqrt {a+b x^2+c x^4} \text {arctanh}\left (\frac {\sqrt {c} x^2-\sqrt {a+b x^2+c x^4}}{\sqrt {a}}\right )\right )}{a^{3/2} \left (-b^2+4 a c\right ) \sqrt {x \left (a+b x^2+c x^4\right )}} \]

[In]

Integrate[Sqrt[x]/(a*x + b*x^3 + c*x^5)^(3/2),x]

[Out]

-((Sqrt[x]*(Sqrt[a]*(b^2 - 2*a*c + b*c*x^2) + (b^2 - 4*a*c)*Sqrt[a + b*x^2 + c*x^4]*ArcTanh[(Sqrt[c]*x^2 - Sqr
t[a + b*x^2 + c*x^4])/Sqrt[a]]))/(a^(3/2)*(-b^2 + 4*a*c)*Sqrt[x*(a + b*x^2 + c*x^4)]))

Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(178\) vs. \(2(87)=174\).

Time = 0.06 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.74

method	result	size
default	\(-\frac {\sqrt {x \left (c \,x^{4}+b \,x^{2}+a \right )}\, \left (2 b c \,x^{2} \sqrt {a}+4 \ln \left (\frac {2 a +b \,x^{2}+2 \sqrt {a}\, \sqrt {c \,x^{4}+b \,x^{2}+a}}{x^{2}}\right ) a c \sqrt {c \,x^{4}+b \,x^{2}+a}-\ln \left (\frac {2 a +b \,x^{2}+2 \sqrt {a}\, \sqrt {c \,x^{4}+b \,x^{2}+a}}{x^{2}}\right ) b^{2} \sqrt {c \,x^{4}+b \,x^{2}+a}-4 a^{\frac {3}{2}} c +2 b^{2} \sqrt {a}\right )}{2 a^{\frac {3}{2}} \sqrt {x}\, \left (c \,x^{4}+b \,x^{2}+a \right ) \left (4 a c -b^{2}\right )}\)	\(179\)

[In]

int(x^(1/2)/(c*x^5+b*x^3+a*x)^(3/2),x,method=_RETURNVERBOSE)

[Out]

-1/2*(x*(c*x^4+b*x^2+a))^(1/2)/a^(3/2)*(2*b*c*x^2*a^(1/2)+4*ln((2*a+b*x^2+2*a^(1/2)*(c*x^4+b*x^2+a)^(1/2))/x^2
)*a*c*(c*x^4+b*x^2+a)^(1/2)-ln((2*a+b*x^2+2*a^(1/2)*(c*x^4+b*x^2+a)^(1/2))/x^2)*b^2*(c*x^4+b*x^2+a)^(1/2)-4*a^
(3/2)*c+2*b^2*a^(1/2))/x^(1/2)/(c*x^4+b*x^2+a)/(4*a*c-b^2)

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 208 vs. \(2 (87) = 174\).

Time = 0.31 (sec) , antiderivative size = 424, normalized size of antiderivative = 4.12 \[ \int \frac {\sqrt {x}}{\left (a x+b x^3+c x^5\right )^{3/2}} \, dx=\left [\frac {{\left ({\left (b^{2} c - 4 \, a c^{2}\right )} x^{5} + {\left (b^{3} - 4 \, a b c\right )} x^{3} + {\left (a b^{2} - 4 \, a^{2} c\right )} x\right )} \sqrt {a} \log \left (-\frac {{\left (b^{2} + 4 \, a c\right )} x^{5} + 8 \, a b x^{3} + 8 \, a^{2} x - 4 \, \sqrt {c x^{5} + b x^{3} + a x} {\left (b x^{2} + 2 \, a\right )} \sqrt {a} \sqrt {x}}{x^{5}}\right ) + 4 \, \sqrt {c x^{5} + b x^{3} + a x} {\left (a b c x^{2} + a b^{2} - 2 \, a^{2} c\right )} \sqrt {x}}{4 \, {\left ({\left (a^{2} b^{2} c - 4 \, a^{3} c^{2}\right )} x^{5} + {\left (a^{2} b^{3} - 4 \, a^{3} b c\right )} x^{3} + {\left (a^{3} b^{2} - 4 \, a^{4} c\right )} x\right )}}, \frac {{\left ({\left (b^{2} c - 4 \, a c^{2}\right )} x^{5} + {\left (b^{3} - 4 \, a b c\right )} x^{3} + {\left (a b^{2} - 4 \, a^{2} c\right )} x\right )} \sqrt {-a} \arctan \left (\frac {\sqrt {c x^{5} + b x^{3} + a x} {\left (b x^{2} + 2 \, a\right )} \sqrt {-a} \sqrt {x}}{2 \, {\left (a c x^{5} + a b x^{3} + a^{2} x\right )}}\right ) + 2 \, \sqrt {c x^{5} + b x^{3} + a x} {\left (a b c x^{2} + a b^{2} - 2 \, a^{2} c\right )} \sqrt {x}}{2 \, {\left ({\left (a^{2} b^{2} c - 4 \, a^{3} c^{2}\right )} x^{5} + {\left (a^{2} b^{3} - 4 \, a^{3} b c\right )} x^{3} + {\left (a^{3} b^{2} - 4 \, a^{4} c\right )} x\right )}}\right ] \]

[In]

integrate(x^(1/2)/(c*x^5+b*x^3+a*x)^(3/2),x, algorithm="fricas")

[Out]

[1/4*(((b^2*c - 4*a*c^2)*x^5 + (b^3 - 4*a*b*c)*x^3 + (a*b^2 - 4*a^2*c)*x)*sqrt(a)*log(-((b^2 + 4*a*c)*x^5 + 8*
a*b*x^3 + 8*a^2*x - 4*sqrt(c*x^5 + b*x^3 + a*x)*(b*x^2 + 2*a)*sqrt(a)*sqrt(x))/x^5) + 4*sqrt(c*x^5 + b*x^3 + a
*x)*(a*b*c*x^2 + a*b^2 - 2*a^2*c)*sqrt(x))/((a^2*b^2*c - 4*a^3*c^2)*x^5 + (a^2*b^3 - 4*a^3*b*c)*x^3 + (a^3*b^2
- 4*a^4*c)*x), 1/2*(((b^2*c - 4*a*c^2)*x^5 + (b^3 - 4*a*b*c)*x^3 + (a*b^2 - 4*a^2*c)*x)*sqrt(-a)*arctan(1/2*s
qrt(c*x^5 + b*x^3 + a*x)*(b*x^2 + 2*a)*sqrt(-a)*sqrt(x)/(a*c*x^5 + a*b*x^3 + a^2*x)) + 2*sqrt(c*x^5 + b*x^3 +
a*x)*(a*b*c*x^2 + a*b^2 - 2*a^2*c)*sqrt(x))/((a^2*b^2*c - 4*a^3*c^2)*x^5 + (a^2*b^3 - 4*a^3*b*c)*x^3 + (a^3*b^
2 - 4*a^4*c)*x)]

Sympy [F]

\[ \int \frac {\sqrt {x}}{\left (a x+b x^3+c x^5\right )^{3/2}} \, dx=\int \frac {\sqrt {x}}{\left (x \left (a + b x^{2} + c x^{4}\right )\right )^{\frac {3}{2}}}\, dx \]

[In]

integrate(x**(1/2)/(c*x**5+b*x**3+a*x)**(3/2),x)

[Out]

Integral(sqrt(x)/(x*(a + b*x**2 + c*x**4))**(3/2), x)

Maxima [F]

\[ \int \frac {\sqrt {x}}{\left (a x+b x^3+c x^5\right )^{3/2}} \, dx=\int { \frac {\sqrt {x}}{{\left (c x^{5} + b x^{3} + a x\right )}^{\frac {3}{2}}} \,d x } \]

[In]

integrate(x^(1/2)/(c*x^5+b*x^3+a*x)^(3/2),x, algorithm="maxima")

[Out]

integrate(sqrt(x)/(c*x^5 + b*x^3 + a*x)^(3/2), x)

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 193 vs. \(2 (87) = 174\).

Time = 0.29 (sec) , antiderivative size = 193, normalized size of antiderivative = 1.87 \[ \int \frac {\sqrt {x}}{\left (a x+b x^3+c x^5\right )^{3/2}} \, dx=\frac {\frac {a b c x^{2}}{a^{2} b^{2} - 4 \, a^{3} c} + \frac {a b^{2} - 2 \, a^{2} c}{a^{2} b^{2} - 4 \, a^{3} c}}{\sqrt {c x^{4} + b x^{2} + a}} - \frac {a b^{2} \arctan \left (\frac {\sqrt {a}}{\sqrt {-a}}\right ) - 4 \, a^{2} c \arctan \left (\frac {\sqrt {a}}{\sqrt {-a}}\right ) + \sqrt {-a} \sqrt {a} b^{2} - 2 \, \sqrt {-a} a^{\frac {3}{2}} c}{\sqrt {-a} a^{2} b^{2} - 4 \, \sqrt {-a} a^{3} c} + \frac {\arctan \left (-\frac {\sqrt {c} x^{2} - \sqrt {c x^{4} + b x^{2} + a}}{\sqrt {-a}}\right )}{\sqrt {-a} a} \]

[In]

integrate(x^(1/2)/(c*x^5+b*x^3+a*x)^(3/2),x, algorithm="giac")

[Out]

(a*b*c*x^2/(a^2*b^2 - 4*a^3*c) + (a*b^2 - 2*a^2*c)/(a^2*b^2 - 4*a^3*c))/sqrt(c*x^4 + b*x^2 + a) - (a*b^2*arcta
n(sqrt(a)/sqrt(-a)) - 4*a^2*c*arctan(sqrt(a)/sqrt(-a)) + sqrt(-a)*sqrt(a)*b^2 - 2*sqrt(-a)*a^(3/2)*c)/(sqrt(-a
)*a^2*b^2 - 4*sqrt(-a)*a^3*c) + arctan(-(sqrt(c)*x^2 - sqrt(c*x^4 + b*x^2 + a))/sqrt(-a))/(sqrt(-a)*a)

Mupad [F(-1)]

Timed out. \[ \int \frac {\sqrt {x}}{\left (a x+b x^3+c x^5\right )^{3/2}} \, dx=\int \frac {\sqrt {x}}{{\left (c\,x^5+b\,x^3+a\,x\right )}^{3/2}} \,d x \]

[In]

int(x^(1/2)/(a*x + b*x^3 + c*x^5)^(3/2),x)

[Out]

int(x^(1/2)/(a*x + b*x^3 + c*x^5)^(3/2), x)